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84b^2+92b=-24
We move all terms to the left:
84b^2+92b-(-24)=0
We add all the numbers together, and all the variables
84b^2+92b+24=0
a = 84; b = 92; c = +24;
Δ = b2-4ac
Δ = 922-4·84·24
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-20}{2*84}=\frac{-112}{168} =-2/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+20}{2*84}=\frac{-72}{168} =-3/7 $
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